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Solution :

The equation of the plane is `vecr=hati-hatj+lamda(hati+hatj+hatk)+mu(hati-2hatj+3hatk)`. <br> Let `" "vecr=xhati+yhatj+zhatk` <br> Hence, the equation is `(xhati+yhatj+zhatk)-(hati-hatj)=lamda(hati+hatj+hatk)+mu(hati-2hatj+3hatk)` <br> Thus, vectors `(xhati+yhatj+zhatk)-(hati-hatj), hati+hatj+hatk, hati-2hatj+3hatk` are coplanar. <br> Therefore, the equation of the plane is `|{:(x-1,,y-(-1),,z-0),(1,,1,,1),(1,,-1,,3):}|=0 or5x-2y-3z-7=0`